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A ball is thrown vertically upward it returns back in the hand of the thrower in 60 seconds how high does it go?
Assuming the ball is thrown in a constant gravitational field causing an acceleration of 9.81 m/s/s (similar to Earth's surface),
y(t) = H + Vt - (g/2)(t^2)
Where H is its original height above your chosen origin, V is its initial upward velocity, g is the acceleration due to gravity (9.81 m/s/s) and t is the number of seconds after throwing it. If we set H to 0 (arbitrarily making the ball's initial height 0) and if are interested in a path wherein the ball takes 60 seconds to return to its original height (0), we say:
y(60) = 0 + V(60) - (g/2)(60^2)
The problem states that it "returns back to the hand" at 60 seconds. This implies that at 60 seconds, it is back at its original position (y(60) = 0)
therefore:
y(60) = 0 = 0 + V(60) - (g/2)(60^2)
We can simplify the expression on the RHS above to find V.
The equation for projectile motion is parabolic with respect to time - this means that, by symmetry, the greatest height is achieved at half the time it takes to return. Plug 30 seconds into the above equation, and I get a result of 4414.5 m. That's almost three miles high!
What else can I help you with?
In throwing a ball upward discuss the velocity and acceleration when the ball returns to the thrower's hand?
A the moment when the ball just touches the thrower's hand, it will have the velocity with which it was thrown and the acceleration will be equal to the acceleration due to gravity at the place acting vertically downwards.
The velocity of a baseball 4 seconds after it is thrown vertically upward with a speed of 32.1 is?
If that's 32.1 meters per second initially, then after 4 seconds it's fallingwith a speed of 7.1 meters per second.If that's 32.1 feet per second initially, then it returns to the thrower's hand injust under 2 seconds, and it's in the dirt long before 4 seconds have passed.If it had been tossed at the edge of a cliff, then after 4 seconds, it would befalling with a speed of 96.7 feet per second.
What is displacement if a ball is thrown up with certain velocity it attains maximum height and comes back to the thrower?
The displacement of the ball from when it was thrown to when it returns to the thrower is zero, as the ball has completed a full round trip back to its initial position. Displacement is a vector quantity that measures the change in position from the initial point to the final point.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
A weapon that comes back to you when thrown?
A boomerang is a weapon that, when thrown, follows a curved trajectory and returns to the thrower. It is designed to come back due to its unique aerodynamic shape and spin. Boomerangs have been historically used for hunting and recreation by Indigenous Australians.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
What is an Aztec spear thrower called?
An Aztec spear thrower is called an atlatl. It is a tool used to increase the velocity and distance of a thrown spear by providing leverage for the thrower.
How long does it take for a ball to hit the ground if it was thrown vertically atop a 2 meter building at 15 meters per second vertically?
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
What is the velocity of an object thrown vertically into the air at its highest point?
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
Which hunting weapon returns when thrown?
boomarang
If a ball is thrown vertically up with the velocity of 40m s what would be its velocity after two seconds?
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
