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Displacemant = Velocity x Time First D1 = 5 x 4 x 60 = 1200 m Then D2 = 4 x 3 x 60 = 720 m Total displacement = D1 + D2 = 1920 m

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A jogger runs in a straight line with an average speed of 5 ms for 4 minutes then finishes with an average speed of 4 ms for 3 minutes. what is his total displacement?

The total displacement of the jogger can be found by adding up the individual displacements from each segment. The displacement for the first segment is (5 m/s) * (4 minutes) = 20 meters. The displacement for the second segment is (4 m/s) * (3 minutes) = 12 meters. Therefore, the total displacement is 20 meters + 12 meters = 32 meters.


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