No, the acceleration at the highest point is never 0.
When an object is thrown upward, the acceleration due to gravity acts downward while the velocity is directed upward. This leads to a decrease in the speed of the object until it reaches its highest point and changes direction.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
0 ms-2 upwards
The acceleration of the object would still be g downward, regardless of the angle at which it is thrown upward. The acceleration due to gravity always acts in the downward direction towards the center of the Earth. The only difference would be the horizontal component of the velocity due to the initial angle of the throw.
When an object is thrown upwards, it loses 9.8 meters per second of speed due to gravity acting against its motion. This is the acceleration due to gravity on Earth, which causes the object to slow down as it moves upward.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
Any object moving under the influence of gravity only and no other outside forces has a constant acceleration of 9.8 meters (32.2 feet) per second2, directed down.The speed changes. The acceleration doesn't, regardless of the angle, speed, trajectory, color, temperature, cost, size, mass, or weight of the falling object.
To find the speed at which the object was thrown upward, we need to know the acceleration due to gravity. Assuming g ≈ 9.81 m/s², the initial speed of the object can be calculated using the equation v = u - gt, where v is the final speed (0 m/s when it returns), u is the initial speed, g is the acceleration due to gravity, and t is the time (6 seconds). This calculation will give you the initial speed at which the object was thrown upward.
To find the time taken for an object to reach the peak of its path when thrown straight upward with a velocity of 50 m/s, you can use the formula: time = velocity / acceleration. Since the object is moving against gravity, the acceleration will be the acceleration due to gravity (-9.81 m/s^2). Therefore, the time taken to reach the peak will be 50 m/s / 9.81 m/s^2 = approximately 5.1 seconds.