Yes. A non-zero force may not be sufficient to alter the velocity - for example if it is smaller that the limiting friction. No change in velocity implies no change in momentum and so impulse = 0.
Impulse is change of momentum, which is force x time over which the force acts. Original momentum = mv, final momentum =0, so impulse is in this case mv.
Zero is an even number, as 0x2= 0.
Work is considered to be zero when the force applied is zero or when there is no displacement of the object in the direction of the force.
0; zero net force
When forces are balanced, the net force is zero.
Zero is even. An integer is even if, when divided by 2, it leaves no remainder. 0/2 = 0, with no remainder.
If the object is moving in a straight line, then the net force on it is zero. If the object is not moving in a straight path, then there is some non-zero net force acting on it even if its speed is constant. We don't have enough information to describe the magnitude or direction of the force.
The impulse given to the object is 40 Ns (Newton-seconds). This is calculated by multiplying the force of 20 N by the time of 2 seconds. Impulse is the change in momentum experienced by an object, and it is equal to the force applied multiplied by the time over which the force is applied.
Not necessarily. The net force being 0 means the object is in translational equilibrium, but the net torque can still be non-zero if there are unbalanced forces causing rotation.
if both normal and tangential force have the value zero.
Work is the scalr product of Force F and displacement D, W=F.D = fdcos(x) if the net force is zero W= 0.d= 0 or no work/
Force is only acting on x axis so y component is actually 0