To create a C program that outputs the sequence 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5, you can use nested loops. The outer loop will iterate through the numbers from 1 to 5, while the inner loop will print each number a number of times equal to its value. Here's a simple implementation:
#include <stdio.h>
int main() {
for (int i = 1; i <= 5; i++) {
for (int j = 0; j < i; j++) {
printf("%d ", i);
}
}
return 0;
}
This program will print the desired output in a single line.
4000 yrs
1) source program to object program 2)object program to object program output
I don't know the language you are using, but the following should do it in c, adapt as needed: int i=1; while(i!=5){ for(int j = 0 ; j < i ; j++){ printf("%d", i); //print i here } i++; //increment i }
two jeroos!!
help me now !!
int main (void) { puts ("1 1 2"); return 0; }
Explain briefly the meaning of an input-output (1/0) bound program, and a processor (CPU) bound program.
<html> <head> <script type="text/javascript"> var n, tally = 0; for(n = 1; n <= 1023; n += 2){ tally += n; } document.getElementByID('output').innerHTML = 'the tally is ' + tally; </script> </head> <body> <div id="output"> </div> </body>
std::cin:get(); I guess it's about TurboC in Windows. 1. Press Alt+F5, to see the program's output 2. Run your .EXE in a separate DOS-window (Command Prompt)
A function-oriented program to calculate the sum of the sequence from 1 to n can be implemented in various programming languages. For example, in Python, you could define a function like this: def sum_sequence(n): return sum(range(1, n + 1)) result = sum_sequence(5) # This will output 15 When the input is 5, the output will be 15, as it sums the numbers 1, 2, 3, 4, and 5.
6,000 (10/1)squared X 60 =6,000 brightness = minification gain x flux gain minification gain = input divided by output squared
It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.