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How do you do the math problem (4-3i)(5 2i)?

Anonymous

∙ 10y ago

Updated: 11/8/2022

To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).

(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2

= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.

Wiki User

∙ 10y ago

What else can I help you with?

What is 2i squared?

This is calculated as follows: (2i)2 = 2i x 2i = 4i2 = 4(-1) = -4.

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It is 6+2i. But -6-2i will also serve.

What is the reciprocal of 2i?

1/2i

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The product in a math is the answer to a multiplication problem.

What is 2-4i over 4 plus 2i put in the form of a plus bi?

To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.

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7 + 2i

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6+2i

What is the conjugate of 6-2i?

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The product is the "sum" of a multiplication math problem.

What does at least mean in a math problem?

In a math problem, least means smallest.

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19.86 - 4.94 math problem = 14.919999999999998

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1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i