The use of more accurate figures for gravity (a) will affect the answer, as does the figure of 16 seconds which limits the significant figures of the answer.
For a = 9.8 m/sec2, the result is 1.3 x 103 meters.
For a = 9.80665 m/sec2, the result is 1255.2512 meters.
First Calculation
Using the equation
s = ut +1/2at2
Where s = displacement, u = initial velocity, a = acceleration & t = time.
Since
u = 0, t = 16s & a = 9.80665 ms2
s = (0 * 16) + (1/2 * 9.8 * 162)
s = 0 + 1255.2512
s = 1255.2512 meters
Second Calculation
First, we must assume that there is negligible air resistance. This is questionable because by analysis, one can see that the stone will be traveling quickly by the time it approaches the ground. However, it is necessary because we do not know any of the characteristics of the stone (dimensions/mass), nor the fluid resistance constant of the air.
Using a common kinematics formula, it is them possible to find the height of the ledge. Note that since the stone falls (rather than being thrown, or the like) it has an initial velocity of zero. The acceleration due to gravity used is 9.8m/s2. A rounded version of the constant is used because the question does not state whereabouts this ledge is, and acceleration due to gravity changes slightly based on where one is.
d=Vit+(1/2)*at2
d=0+(1/2)*(9.8m/s2)(16s)2
d=1254.4m
Considering significant figures, the height of the ledge is 1.2x103m.
Third Calculation
Assuming that air resistance is negligible, the ledge is 1254.4 meters tall.
Use the kinematics equation x = 0.5at2 + v0t + x0
where a stands for acceleration, t for time, v0 for initial velocity, and x0 for initial position.
We are given that v0 = 0. We can also say that the top of the ledge is x0 and that x0 = 0. Furthermore since we assumed that the only force acting on the stone is gravity, gravity is the force that will provide the acceleration. Thus, a = g = 9.8m/s2.
Putting this all together we get x = 0.5(9. 8m/s2)(16 sec)2 + (0)(16 sec) + 0 = 1254.4 m.
Note that if you are using significant figures the answer will be 1.3 x 103 m.
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A stone that falls from a ledge and takes 8 second to hit the ground travels a distance of 313.6 meters. You can find this answer by substituting 8 seconds for time in the physics formula d = 1/2 x acceleration x (t squared), where d = distance, acceleration is given as a =9.8 meters/second squared, and t squared is time in seconds.
92.2m/s
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
The approximate gravitational acceleration on Earth is 9.8 meters per second. Neglecting air friction is s equals 4.9 times 16 squared. S is equal to 1254.4 meters which is equal to 4100 feet.
A 92.2 m/s V = (4 m/s) + (9.8 m/s²) (9 s) V = 92.2 m/s
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
D. 36 m/s
The time required for a stone to fall from a given height can be calculated mathematically. Time equals the square root of two times the distance divided by force of gravity. Time is in seconds, distance in meters, and the force of gravity on Earth is 9.8 meters/second ^2.
A stone falls freely from rest The total distance covered by it in the last second of its motion equals the distance covered by it in the first three seconds How long does the stone remain in air?
If a stone falls from a ledge and takes 16 seconds to hit bottom, then the bottom is 1413 meters away. This assumes acceleration due to gravity of 9.81 meters per second squared, an initial velocity of zero, and no friction due to air resistance. Air resistance will decrease the distance.x = 1/2 at2 + v0t + x0
The vikings, on the top ledge