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What else can I help you with?
Equation for constant volocity?
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
What is the velocity equation?
If the velocity is constant then it is enough to use the equation, s = vt. S- the displacement, t - time elapsed and v the uniform or constant velocity. If velocity changes, then acceleration is there in action. Hence the final velocity after time t will be given as v = u + at.
What is the equation for uniform velocity?
V = constant Speed = constant Direction = constant Acceleration = 0
If the velocity is constant describe the slope of the graph on a position vs. time graph.?
If velocity is constant, the slope of the graph on a position vs. time graph will be a straight line. The slope of this line will represent the constant velocity of the object.
What is the slope of constant velocity?
The slope of a position-time graph for an object moving with constant velocity is equal to the velocity of the object. This is because velocity is the rate of change of position with respect to time, and a constant velocity means the object is covering equal distances in equal time intervals.
What is continuity equation in fluid mechanics?
Area*Velocity=Constant
What is an object that moves with constant position?
An object that moves with constant position will have constant velocity or acceleration. This is said to be moving in positive direction and maintains the position.
What is the derived equation of velocity?
Velocity is derived from position - it is defined as the rate of change of position. In symbols: v = ds/dt Where v = velocity, s = position, and t = time. For the case of constant velocity, this can also be written as: v = (difference in position) / (time elapsed)
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
What is the formula for position with constant velocity?
Positive velocity: p=vt (position = velocity*time) Example: Write the position equation for a person who starts 3 meters behind the reference point and walks with a constant velocity v=6 m/s in the positive direction. Answer: p=-3+6t Example: What is the position of the person 5 seconds after the start of motion? Answer: p=-3+(6x5)=27 m. Negative velocity: p=p(0)+vt p(0) represents the position at time "0" which is also known as the y-intercept or the point where the line crosses the vertical axis. The velocity of the object in motion would be negative.
Is it true that particle with a position that is given by 𝑥(𝑡) 𝐴𝑡 plus 𝐵 (A and B are properly dimensioned constants) is moving with a constant velocity?
No, a particle with position given by 𝑥(𝑡) = 𝐴𝑡 + 𝐵 is not moving with constant velocity, it is moving with a constant acceleration since its position is changing linearly with time. Velocity would be given by the derivative of 𝑥(𝑡) which would be a constant.
Is there is any linear or Circular motion equation or just the motion in which acceleration of body changes at constant velocity?
The question is, if not a maelstrom, certainly a melange at least.Especially noteworthy is the part where "acceleration of a body changesat constant velocity".Acceleration is the rate of change of velocity. If velocity is constant, then there isno acceleration. If velocity changes at a constant rate, then acceleration is constant.Velocity would have to change at a rate that changes, in order to have a changingacceleration.Now, what is it you're looking for ? A "linear or circular motion equation" ? There areoodles of them, describing the relationship among the position, displacement, speed,velocity, and acceleration, in one, two, or three dimensions, in rectangular, polar, andspherical coordinates, for linear motion, and an entire separate set of equations forcircular motion.
