To determine if 76380 is divisible by these numbers, we can check the necessary conditions. It is even, so it is divisible by 2. The last digit is 0, which means it is divisible by 10 and 5. The sum of the digits (7 + 6 + 3 + 8 + 0 = 24) is divisible by 9, so 76380 is also divisible by 9. Finally, since it is divisible by 3 (the sum of the digits is divisible by 3), 76380 is divisible by all the numbers listed: 2, 3, 5, 9, and 10.
Yes.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
It is evenly divisible by 2 and by 3.
Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;