It depends on the masses of the blocks and the coefficients of friction. If the force of friction between the lower block and the ramp is greater than the force of friction between the upper and lower blocks, the upper one will accelerate at a greater rate than the lower one, and it will fall off. Otherwise, they will accelerate together.
The acceleration of the connected blocks is the same because they are moving together.
Cut blocks are, but chop blocks are not. Both should be against the rules.
The combined mass of the two blocks will be twice the original mass. If twice the original force is applied, the acceleration will be the same as the original acceleration because the net force acting on the blocks (twice the original force) is proportional to the mass of the blocks (twice the original mass), resulting in the same acceleration.
you can't play
u can't phone them
Nothing happens.
If one Newton of force accelerates 1 block at 1 m/s^2, applying twice the force to a container with 4 blocks would result in an acceleration of 0.5 m/s^2. This is because the total mass of the system (the container and 4 blocks) has increased, requiring more force to achieve the same acceleration.
To determine the tension between two blocks, you can use the equation T m g, where T is the tension, is the coefficient of friction between the blocks, m is the mass of the blocks, and g is the acceleration due to gravity. This equation helps calculate the force required to overcome friction and move the blocks.
A total lunar eclipse happens when the Earth blocks out the moon entirely from the sun.
when a solar eclipse happens the sun is perfectly alined with the moon. when this happens the moon blocks the sun causing the sun to show no light.
All what happens is that you can't favorite or retweet their tweets, but when you mention them, it won't show up in their notifications.
At pinch off voltage, the channel is blocked at its maximum. (depletion region blocks almost entire channel, so no charge exchange). Therefore, no drain is flown through the channel.