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To find ( i^{116} ), we can use the property that ( i ) (the imaginary unit) has a cycle of four: ( i^1 = i ), ( i^2 = -1 ), ( i^3 = -i ), and ( i^4 = 1 ). To determine ( i^{116} ), we calculate ( 116 \mod 4 ), which gives a remainder of 0. Therefore, ( i^{116} = i^0 = 1 ). The answer is C) 1.

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3w ago

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