What is the tension in the string if a stone of mass 300 grams tied to one end of the string in a horizontal plane is whirled round in a circle of radius 1meter with the speed of 50 revolution per min?

Answer 1

We can determine the tension using the formula F = mv2/r. But first, we need to find v. The circumference of the circle is 6.28 meters. (2piR). The stone goes around this circle 50 times every minute (6.28 m X 50 revolutions = 314 meters per minute). We can divide this quantity by sixty to get the speed in meters per second (5.23 m/s). Now we plug in our values into F = mv2/r. (.3 kg)(5.23 m/s)2/(1 meter) = 8.216 Newtons