How can a force be perpendicular to a point?! Surely you wanted to ask "Why no work is done when force is perpendicular to the direction of the displacement of the body?". This finds a simple answer in the definition of work: work done by a force F is defined as
W := ∫ Fdr,
where r is the position of the particle (that is, of the point of the body the force acts on), and hence dr is the direction of the displacement of the particle. From the definition, you immediatly see that if the angle between F and dris 90° (or, in general, (2n + 1)π/2, with n element of Z) the scalar product is Fdr = 0, and thus W = ∫0 = 0.
If the angle between the force and the direction of motion of a body is 90 degrees (perpendicular), then the work done is zero. This is because the component of force in the direction of motion is zero, resulting in no work being done on the object.
The work done by a body moving along a circular path is zero if the force is perpendicular to the direction of motion, such as in the case of centripetal force. This is because the displacement is perpendicular to the force. If there is a component of the force in the direction of the motion, work is done, calculated as the dot product of the force and displacement vectors.
When a force and displacement are perpendicular to each other, no work is done because the force is not acting in the same direction as the displacement. Work is defined as the product of force and displacement in the direction of the force, so when they are perpendicular, the force does not contribute to the displacement and no work is done.
No. At least not by the force that's perpendicular to the motion. When you push a baby stroller (or a car), you do work, but the force of gravity, downward and perpendicular to the motion, doesn't.
True. When the force is perpendicular to the direction of motion, no work is done because work is the product of force and displacement in the direction of the force. Since there is no displacement in the direction of the force, no work is done.
When a force is perpendicular to the direction of motion, no work is done. This is because work is defined as the product of force and displacement in the direction of the force. If the force is perpendicular, then there is no displacement in the direction of the force and thus no work is done.
Centripetal force refers to the force that acts on a body moving in a circular path. It does not do work on an object because it acts perpendicular to the motion of the body. The work done on a rotating object is zero.
Zero, in this case acting force is perpendicular to the direction of displacement... Reason..... It is because here the angle is 90 degree and when there is an angle then the force is equal to F cos x * d= F *cos 90*0= 0 Therefore work done=0
No work is done against gravity when a body is moved horizontally along a frictionless surface because the force of gravity acts perpendicular to the direction of motion. Work is only done when a force is exerted in the direction of motion.
Yes, that is possible. For example, an object in circular motion, accelerated towards the center. The force (and the acceleration) is normal (perpendicular) to the movement; thus, the dot product between the force and the displacement is zero.
Work is not done on an object when there is no displacement of the object in the direction of the force applied. In other words, if the force and the displacement are perpendicular to each other, no work is done. Additionally, if there is no force acting on an object, no work is being done on it.
Zero. This is because when a body when around in a circle, a centripetal force acts on the particle to keep it at that fixed distance from the centre. At each point, the force and the displacement are perpendicular to each other. Hence no work is done. The answer is NOT Zero! A Force is required in the direction of motion around the circle. At every point (an infinite number of them) there must be a Force PERPENDICULAR to the Centrifugal and Centripetal Forces or the object would not move. Therefore the amount of work done is the product of that FORCE times the circumference of the circular path, if only considering one revolution.