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If I rolled one die twice what is the probability that i would get a even number for my first roll and a 1 for my second roll?
To find the probability of rolling an even number on the first roll and a 1 on the second roll with a single die, we first note that the even numbers on a die are 2, 4, and 6. Thus, the probability of rolling an even number on the first roll is 3 out of 6, or 1/2. The probability of rolling a 1 on the second roll is 1 out of 6. Therefore, the combined probability is (1/2) * (1/6) = 1/12.
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What is the probability of rolling a 2 or a 4 on the second die given that you roll an even number on the first die?
The probability of rolling a 2 or a 4 on the second die is independent of the outcome of the first die. A standard die has six faces, with three even numbers (2, 4, and 6). Therefore, the probability of rolling a 2 or a 4 on the second die is 2 out of 6, or 1/3, regardless of whether an even number was rolled on the first die.
Two number cubes are rolled what is probubility of 1 and 2?
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
What is the probability of rolling the same number when three number cubes are rolled?
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
A number cube was rolled as part of an experiment. The results are shown in the table. Explain how to find the experimental probability of rolling a 6.?
To find the experimental probability of rolling a 6, you first need to determine the number of times a 6 was rolled during the experiment. Then, divide that number by the total number of rolls recorded in the table. The resulting fraction represents the experimental probability of rolling a 6. For example, if a 6 was rolled 5 times out of 30 total rolls, the experimental probability would be 5/30, which simplifies to 1/6.
What is the probability of showing an even number on the first die and an odd number on the second die?
25%
What is the probability of rolling a 2 on the first dice and an odd number on the second dice?
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
How to solve probability questions?
Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.
Two standard dice are rolled Let A be the event that the first die lands on a number less than 4 Let B be the event that the second die lands on 5?
The first event is Less than 4, which is either 1, 2, or 3. The probability of this is 1/2.The second event is die number = 5. The probability of this is 1/6.Multiply the two probabilities together: (1/2)*(1/6) = 1/12 (about 8.33 % chance).
You roll two number cubes what is the probability that you roll a 1 first and a 2 second?
Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
What is theoretical probability of picking 2 squared numbers out of 15?
The answer depends on whether the first number is replaced before picking the second. If not, the probability is 0.029
If a game there are two fair number cubes that are rolled To make the first move you need to roll a total of 6 or 7 or 8 What is the probability that you will be able to make the first move?
Three out of twelve
