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If a farmer has 13 cows and all but 9 die how many cows does he have left?
If a farmer starts with 13 cows and all but 9 die, he would have 9 cows left. The phrase "all but 9" means everything except 9. So, if all the cows except 9 die, those 9 remaining cows are what the farmer has left.
A farmer had 12 cows All but 9 die How many cows did he have now?
he has 9
How many cows does the farmer have left if he starts with seventeen cows and all but eight die?
The farmer has eight cows, since all but that many died.
A farmer had 12 cowsAll but 9 die How many cows did he have now?
Nine.
If the farmer decided to keep 10 cows and got rid of 9 how many does he have?
10 Cows. Ten. He Decided to Keep 10 cows, so that is how many he has. He must have had 19 to begin with; since he gave 9 away.
How do you fit 9 pigs to 8 pens?
Eat onr
If a farmer has 9 sheep and 1 large pen and 3 small pens how does he get 1 sheep in each pen?
eat 5 sheep
Forty-eight pens are packaged in 4 boxes. How many pens are packaged in 9 boxes?
In 4 boxes there are a total of 48 pens. Divide 48 by 4 and this will give you how many pens are in 1 box. 48/4 = 12. To find how many pens are in 9 boxes multiply 12 by 9. 12x9 = 108. There are 108 pens in 12 boxes
If a farmer had 17 sheep and all but 9 died how many did he have left?
9 live and the rest die look at the question carefully and you'll find the answer.
Forty eight pens are packaged in 4 boxes. How many pens are packaged in 9 boxes?
108
Can a farmer put 9 ostriches in 4 pens so that there is an odd number of ostriches in each pen so that each pen has at least one ostrich?
No. The sum of four odd numbers will always be an even number!
Four black cows and three brown cows give as much milk in five days as three black cows and five brown cows give in four days Which color cow is a better milker and why?
The black cows are the better milkers because the amount of milk they produced per cow is greater than that from the brown cows. This is a simple algebra problem. Let x = black cow and y = brown cow, solving as such: 4x = 5 3x = 4 3y = 5 5y = 4 4x + 3x = 9 7x = 9 x = 9/7 = 1.29 units per black cow 3y + 5y = 9 8y = 9 y = 9/8 = 1.13 units per brown cow
