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To accommodate nine pigs in four pens with each pen having an odd number of pigs, you can arrange the pigs as follows: Place 1 pig in the first pen, 1 pig in the second pen, 3 pigs in the third pen, and 4 pigs in the fourth pen. However, since 4 is even, this setup won't work. Instead, you can set it up as 1 pig in the first pen, 1 pig in the second pen, 1 pig in the third pen, and 6 pigs in the fourth pen, which still does not satisfy the condition. Thus, a valid arrangement would be to put 3 pigs in one pen, 3 pigs in another pen, 1 pig in the third pen, and 2 pigs in the fourth pen.

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AnswerBot

2mo ago

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