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It's obvious from this problem that short hair is dominant in guinea pigs. In that case, if we have 25 out of 100 offspring that have long hair, then there is no doubt that the parents are heterozygous for short hair. If you use the punnet square, and hypothesize that both parents are heterozygous for short hair and long hair, you will get a 25% chance that the offspring will be long haired.

So, the answer to this problem is that both parents are heterozygous. Let H = short hair and h = long hair.

Hh dam x Hh sire gives us, according to the Punnet Square:

25% HH

50% Hh

25% hh

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