Red. Red is the most recessive gene in coat colouration in cattle, thus the parents can only be homozygous red in order to give a red calf. If red as mixed with another gene, like white or black, it would not show in the calf completely or not show at all, respectively. Thus, the bull must be homozygous red (rr) and the cow must be homozygous red (rr) in order to produce red offspring.
The genotype of the offspring that had the same phenotype as the parents is rr or wrinkled. The phenotype for the seed shape of both parent plants is round.
normal sexual cross pollination - each parent plant contributes traits from its genotype (which are expressed as the phenotype)
That is most likely called the phenotype, as apposed to the genotype of the offspring.
Try using a Punnett Square.
If 50% of the offspring show the dominant phenotype and 50% show the recessive phenotype, it is likely that one parent is heterozygous (Aa) for the trait and the other parent is homozygous recessive (aa). This would result in a 1:1 ratio of offspring showing each phenotype.
In a test cross, one individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. The genotype of the individual with the dominant phenotype can then be inferred based on the phenotypic ratios of the offspring.
The statement that a phenotype determines genotype is false; rather, a genotype, which consists of allele combinations, determines the phenotype. A gamete indeed receives only one allele from each pair during meiosis, ensuring that offspring inherit one allele from each parent. Therefore, the inheritance of traits is based on the genetic information carried in the genotype, which ultimately influences the observable characteristics, or phenotype.
In a testcross, an individual with a dominant phenotype but unknown genotype is crossed with an individual that is homozygous recessive for the same trait. This helps determine the unknown genotype of the dominant individual based on the phenotypic ratios of the offspring. If any offspring display the recessive phenotype, it indicates that the dominant parent is heterozygous. Conversely, if all offspring show the dominant phenotype, the dominant parent is likely homozygous.
No. It is possible for the reverse to be true, two organisms can have the same phenotype but a different genotype. This is because the phenotype is what you will see on the outside whereas the genotype is the combination of alleles and since this determines the phenotype, two organisms with the same genotype will have the same phenotype. So, basically, no. Actually 2 organisms can certainly have different phenotypes with the same genotype--this refers to the concept of penetrance. Some people can have the gene for a condition but never show symptoms. An excellent example of this is the disease neurofibromatosis. This disease has very variable penetrance in which a child of an affected parent may show no signs of the disease, but then have a child with a severe form.
When all offspring have the same phenotype and genotype as the parent, this is known as asexual reproduction or cloning. In this process, a single organism replicates itself, producing genetically identical offspring. This can occur in various organisms, such as bacteria, certain plants, and some animals, ensuring that the traits of the parent are passed on unchanged to the next generation. As a result, there is little to no genetic diversity among the offspring.
The probability that the offspring of a homozygous dominant parent (AA) and a heterozygous parent (Aa) will show a recessive phenotype is 0%. Since the homozygous dominant parent contributes only dominant alleles (A), all offspring will inherit at least one dominant allele (A) from the homozygous parent, resulting in either a homozygous dominant (AA) or a heterozygous (Aa) genotype, both of which express the dominant phenotype.
both must be tt or both must be Tt