4 full adders will be used BCD is a 4 bit code. Each bit of the BCD number will be an input of each full adder. input 1 in first FA. 1 in second and 0 in the last to FA's
A subtractor can be designed using the same aproach as that of an adder ,subtractor are usually implemented within a binary adder for only a small cost when using the standard two's complement notation,by providing an addition/subtraction sector to the carry in and invert the second operand. A subtractor using of diffrencate bits.
When you construct and use a table to solve a problem, you are using a numerical approach.
By using a protractor and a straight edge
if you want to use 8*3 encoder than you must the design the circuit according to variable and with the help of k-map and you can not construct the circuit of 8*3 encoder using 7432 (which is or gate ic) only. you need AND gate 7408 and may be NOT 7404 gate according to design.
yes
Logic circuit forplementation of a full adder using decoder and 2 or gate? Read more:Logic_circuit_forplementation_of_a_full_adder_using_decoder_and_2_or_gate
ab+bc
20
Use the multiplexer to choose the correct output based on the inputs (use the truth table).
by the procedure design a half subtractor design a logic ciruit to add two numbers with five bits each drawthe logic diagram of afull adder using using NAND gates only ?
The adder is a poisonous snake. Using binary numbers, the adder produced a mathematical outcome.
Do you mean :- how to get full adders by using half-adders? For this question refer following answer - A full-adder can be obtained by combining two half-adders and one or gate. Details on full-adder and half-adder can be referenced from following link http://www.fullchipdesign.com/fulladder.htm
A "half adder" circuit computes the resulting bit and carry bit from adding two bits together, assuming there is no carry (using an "exclusive-or" and an "and" operation, respectively). This is sufficient for the lowest-order bit, only; the remaining bit positions require a "full-adder" circuit to compute the result and carry from three inputs at each successive bit position (i.e. the two operands and the carry-in from the previous bit position).
An operational amplifier (op-amp) can be configured as an adder using a summing amplifier circuit. In this configuration, multiple input voltages are fed into the inverting terminal through resistors. The op-amp produces an output voltage that is proportional to the negative sum of the input voltages, scaled by the resistor values. By using feedback and appropriate resistor ratios, the circuit can be designed to add the input voltages with desired gain or weighting.
Any hardware whatsoever satisfies the conditions of this question ... as long as it hasthree input lines ... since the question neglects to specify what it wants the circuit to dowith the 3-bit input number.
12 NOR gates are required to implement full adder
By using 5 NOR gates, we can implements half-subtractor. The inputs for 1st NOR gate are A and B, for 2nd NOR gate inputs are the output of 1st NOR gate and A input, for 3rd NOR gate inputs are the output of 1st NOR gate and B input, for 4th NOR gate the inputs are gates 2 and 3, and for last gate input is the output of the 4th gate.