0
Anonymous
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011
af=0
sf=1
zf=0
cf=0
b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010
af=1
sf=0
cf=1
Wiki User
The answer to this would be 5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1. This would be how this should be worked out to get the correct answer that af=0 and sf=1.