Basically, you just have to figure out what each number is and add the two (same for subtracting).
Let's say you have this problem...
I + VI
Since I is one and VI is six, you'd add 1+6.
If you had...
VII - II
You'd take 7 minus 2, since VII is 7 and II is 2.
Here are the numbers 1-10. 1=I 2=II 3=III 4=IIII 5=V 6=VI 7=VII 8=VIII
9=IX 10=X Hope I helped! (P.S. If you don't know how to add or subtract regularly, you have a rather large problem on your hands. :-) )
IX = 9
If you mean CD plus DC then in Roman numerals they add up to M meaning 400 plus 600 = 1000
MCMLXXX is the number 1980 in roman numerals. The XXX in last is to add 30 to make the last numbers 80.
With great difficulty because 1444 in Roman numerals in today's terms are MCDXLIV and to add them to DLV (555) is an almost impossible task. But the Romans probably calculated the above numbers on a abacus calculating board as:- MCCCCXXXXIIII + DLV = MDCCCCLXXXXVIIII = IMM (-1+2000=1999) when simplified. The rules governing today's Roman numeral system were not the same rules in which the Romans themselves actually used because they were changed in the Middle Ages presumably to make it easier to convert Roman numerals into Hindu-Arabic numerals that were gradually being introduced into Western Europe.
I would convert them back into Hindu-Arabic numerals, do the addition and then convert the answer to Roman numerals.
Convert from Roman numerals to Arabic numerals, add, convert back to Roman numerals.
XXVII (27 in Roman numerals) added to XL (40 in Roman numerals) equals LXVII, which is 67 in Roman numerals.
1132 in Roman Numerals is MCXXXII. M=1000, add C=100 then you add XXX=30 and last, II=2.
IX = 9
If you mean CD plus DC then in Roman numerals they add up to M meaning 400 plus 600 = 1000
MCMLXXX is the number 1980 in roman numerals. The XXX in last is to add 30 to make the last numbers 80.
With great difficulty because 1444 in Roman numerals in today's terms are MCDXLIV and to add them to DLV (555) is an almost impossible task. But the Romans probably calculated the above numbers on a abacus calculating board as:- MCCCCXXXXIIII + DLV = MDCCCCLXXXXVIIII = IMM (-1+2000=1999) when simplified. The rules governing today's Roman numeral system were not the same rules in which the Romans themselves actually used because they were changed in the Middle Ages presumably to make it easier to convert Roman numerals into Hindu-Arabic numerals that were gradually being introduced into Western Europe.
I would convert them back into Hindu-Arabic numerals, do the addition and then convert the answer to Roman numerals.
None because Big Ben is the name of a bell surrounded by 4 clocks.
They could be 6 Roman numerals that add up to DC = 600
It is: XXIII+IX = XXXII
Arabic(Modern) = 11 Roman = XI Here are the first 20 Roman Numerals 1 = I 2 = II 3 = III 4 = IV ( or IIII on classic dials of clocks). 5 = V 6 = VI 7 = VII 8 = VIII 9 = IX 10 = X 11 = XI 12 = XII 13 = XIII 14 = XIV 15 = XV 16 = XVI 17 = XVII 18 = XVIII 19 = XIX 20 = XX NB The first ;12; numbers you will find on analogue clocks with a classic dial.