449 in roan numbers is CDXLIX
In todays modern notation of Roman numerals it is: CDXLIX But the ancient Romans probably wrote it out simply as ID which means 500-1
449 is indeed a prime number. It has no positive integer factors other than itself and one.
Today we would convert these numbers into Roman numerals as CDIII, XCIX XLIX and CDXLIX respectively which makes addition of them almost impossible. However, notwithstanding the above the Romans probably wrote out the equivalent of 403, 99, 49 and 449 in a simplified format as CDIII, IC, IL and ILD respectively which makes addition of them straightforward as follows:- CDIII+IC = DII (403+99 = 502) DII+IL = DLI (502+49 = 551) DLI+ILD = M (551+449 = 1000) Alternatively the Romans could have used an abacus counting device to add together these numerals in their expanded format:- CCCCIII+LXXXXVIIII = DII (403+99 = 502) DII+XXXXVIIII = DLI (502+49 = 551) DLI+CCCCXXXXVIIII = M (551+449 = 1000) Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1
To convert 50.449 into a mixed number, first, identify the whole number and the fractional part. The whole number is 50, and the decimal 0.449 can be expressed as the fraction 449/1000. Thus, 50.449 as a mixed number is ( 50 \frac{449}{1000} ).
449% = 449/100 in fraction
Do you mean Roman language or Roman numerals? In language 449 is quadringenti-ae-a quadraginta novem. In numerals it is CCCCXLIX
In todays modern notation of Roman numerals it is: CDXLIX But the ancient Romans probably wrote it out simply as ID which means 500-1
Originally there were two, but by 449 BC the number had increaed to ten.
CDXLIX
Fake number
The number is 1.
449 is indeed a prime number. It has no positive integer factors other than itself and one.
Today we would convert these numbers into Roman numerals as CDIII, XCIX XLIX and CDXLIX respectively which makes addition of them almost impossible. However, notwithstanding the above the Romans probably wrote out the equivalent of 403, 99, 49 and 449 in a simplified format as CDIII, IC, IL and ILD respectively which makes addition of them straightforward as follows:- CDIII+IC = DII (403+99 = 502) DII+IL = DLI (502+49 = 551) DLI+ILD = M (551+449 = 1000) Alternatively the Romans could have used an abacus counting device to add together these numerals in their expanded format:- CCCCIII+LXXXXVIIII = DII (403+99 = 502) DII+XXXXVIIII = DLI (502+49 = 551) DLI+CCCCXXXXVIIII = M (551+449 = 1000) Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1
CDXLIX uses several different symbols for the numbers. In this case it would be 449.
To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.
449
1993 Upper Deck RC #449 Derek Jeter $15