The number of combinations of three balloons that can be chosen from ten balloons can be calculated using the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 10 ) and ( r = 3 ). Thus, the calculation is ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 different combinations of three balloons that can be chosen from ten.
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
An infinite number of combinations of fractions can be aded together to equal three fourths.
6
5C3 = 10
6 Is how many different combinations there are
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
Four outcomes, three combinations.
It is: 15C7 = 6435 combinations
Three combinations: 23, 24 and 34
4
6 different combinations can be made with 3 items
An infinite number of combinations of fractions can be aded together to equal three fourths.
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
ans : 3720
10
6
5C3 = 10