64 in Roman numerals is LXIV
64 - LXIV
LXIV
Roman numerals don't have a 0 symbol and so it is an invalid arrangement of Roman numerals
In Roman numerals, twelve is represented by the symbol "XII".
Zero cannot be represented in Roman Numerals.
64 - LXIV
64 = LXIV in Roman numerals.
LXIV
Roman numerals don't have a 0 symbol and so it is an invalid arrangement of Roman numerals
In Roman numerals, twelve is represented by the symbol "XII".
The lack of a zero symbol creates no problems with Roman numerals.
Zero cannot be represented in Roman Numerals.
The Roman numerals for 27 are XXVII. In Roman numerals, the symbol "X" represents 10, the symbol "V" represents 5, and the symbol "I" represents 1. Therefore, "XX" represents 20, "V" represents 5, and "II" represents 2, which when combined, gives us 27.
The number 64 in roman numerals is written as LXIV.
2009 in Roman numerals is MMIX.
The Roman numerals for 64 are ILXV (65-1) or LXIIII (64) and they are not LXIV. So your question is: What is the cube root of LXIIII in Arabic numerals? The answer is 4 which is IIII or IV in Roman numerals.
Roman numerals do not include a symbol for zero, so zero cannot be rendered in Roman numberals.