1 = I 5 = V 10 = X 50 = L 100 = C Therefore, all other numbers between 1 and 100 are made up of a combination of these letters, with a maximum of three of the same letter in a row. If 8 = VIII, then 18 = 10 + 8, i.e. XVIII. If 9 = one before 10, i.e. IX, then 19 = 10 + 9, i.e. XIX and so on. Roman Numerals 1-100
1= I
2 = II
3 = III
4 = IV
5 = V
6 = VI
7 = VII
8 = VIII
9 = IX
10 = X
11 = XI
12 = XII
13 = XIII
14 = XIV
15 = XV
16 = XVI
17 = XVII
18 = XVIII
19 = XIX
20 = XX
21 = XXI
22 = XXII
23 = XXIII
24 = XXIV
25 = XXV
26 = XXVI
27 = XXVII
28 = XXVIII
29 = XXIX
30 = XXX
31 = XXXI
32 = XXXII
33 = XXXIII
34 = XXXIV
35 = XXXV
36 = XXXVI
37 = XXXVII
38 = XXXVIII
39 = XXXIX
40 = XL
41 = XLI
42 = XLII
43 = XLIII
44 = XLIV
45 = XLV
46 = XLVI
47 = XLVII
48 = XLVIII
49 = XLIX
50 = L
51 = LI
52 = LII
53 = LIII
54 = LIV
55 = LV
56 = LVI
57 = LVII
58 = LVIII
59 = LIX
60 = LX
61 = LXI
62 = LXII
63 = LXIII
64 = LXIV
65 = LXV
66 = LXVI
67 = LXVII
68 = LXVIII
69 = LXIX
70 = LXX
71 = LXXI
72 = LXXII
73 = LXXIII
74 = LXXIV
75 = LXXV
76 = LXXVI
77 = LXXVII
78 = LXXVIII
79 = LXXIX
80 = LXXX
81 = LXXXI
82 = LXXXII
83 = LXXXIII
84 = LXXXIV
85 = LXXXV
86 = LXXXVI
87 = LXXXVII
88 = LXXXVIII
89 = LXXXIX
90 = XC
91 = XCI
92 = XCII
93 = XCIII
94 = XCIV
95 = XCV
96 = XCVI
97 = XCVII
98 = XCVIII
99 = XCIX
100 =C
In Roman Numerals, C is 100 and I is 1 so CCI would be 100+100+1 or 201.
1-100 = I-C in Roman numerals
212 in Roman numerals is CCXII (100+100+10+1+1 = 212)
dcccxviii (in capital letters) 500+100+100+100+10+5+1+1+1
Google "list roman numerals 1 1000" there's a website.
In Roman Numerals, C is 100 and I is 1 so CCI would be 100+100+1 or 201.
1-100 = I-C in Roman numerals
212 in Roman numerals is CCXII (100+100+10+1+1 = 212)
There is not enough space to list 3,214 Roman numerals here!
dcccxviii (in capital letters) 500+100+100+100+10+5+1+1+1
Google "list roman numerals 1 1000" there's a website.
202 100 + 100 + 1 + 1
If u would like a list, go to... http://www.romannumerals.co.uk/roman-numerals/numerals-list.html
CIOO
CLXIII(ie. 100 + 50 + 10 + 1 + 1 + 1)
The Roman Numeral for 2,803 is: MMDCCCIII.That Translate too:MM = 1000 + 1000D = 500CCC = 100 + 100 + 100III = 1 + 1 + 1MMDCCCIII = 1000 + 1000 + 500 + 100 + 100 + 100 + 1 + 1 +1 = 2,803.
Assuming they are Roman Numerals 100 + 100 + 1 + 1 + 1 = 203