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Why is XIIC is not a valid Roman numbers?
XIIC The table of Roman Numerals M = 1000 D = 500 C = 100 L = 50 X = 10 V = 5 I = 1 The rules for composing Roman numerals is ;- Largest value to the left followed by the lesser values to the right. e.g. MDCLXVI = 1000 + 500 + 100 + 50 + 10 + 5 + 1 = 1666. Multiples of the same value are shown as the same repeated letter. e.g. MM = 1000 + 1000 = 2000 If a lesser value (one letter only) is shown to the left of a larger value it means subtract. e.g. IV = 5(V) - 1(I) = 4 or MCM = 1000 - ( 1000 - 100) = 1000 + 900 = 1900. The current years of 2023 is MMXXIII. Next year , 2024 is written as MMXXIV So your question of 'XIIC' is incorrect. because you have three lesser values to the left of the greater value. ; only one symbol allowed. The 'C' is in the wrong place. Try CXII = 100 + 10 + 1 + 1 = 112. It is NOT read as (10 + 1 + 1 -(100) = 12 - 100 = 88. '88' in Roman numerals is LXXXVIII. Hope that helps!!!!
What does XIIC in roman numerals?
If it were valid, XIIC would be 88 because: X=10, I=1, C=100 and any smaller number written before a larger one should be deducted from the larger number - so, 10+1+1=12 and 100-12=88. However, 88 would actually be written LXXXVIII (where L=50 and V=5) which is 50+10+10+10+5+1+1+1 as it was the custom to have only one instance of a smaller number before a larger one. For example, 90 is XC (100-10) but 80 is LXXX (50+10+10+10) and 99 is IX (100-1) but 98 is LXLVIII (50+(50-10)+5+1+1+1). However, they did sometimes break the rules - IIC is much easier to write for 98!
Why is XIIC is not a valid Roman numbers?
XIIC The table of Roman Numerals M = 1000 D = 500 C = 100 L = 50 X = 10 V = 5 I = 1 The rules for composing Roman numerals is ;- Largest value to the left followed by the lesser values to the right. e.g. MDCLXVI = 1000 + 500 + 100 + 50 + 10 + 5 + 1 = 1666. Multiples of the same value are shown as the same repeated letter. e.g. MM = 1000 + 1000 = 2000 If a lesser value (one letter only) is shown to the left of a larger value it means subtract. e.g. IV = 5(V) - 1(I) = 4 or MCM = 1000 - ( 1000 - 100) = 1000 + 900 = 1900. The current years of 2023 is MMXXIII. Next year , 2024 is written as MMXXIV So your question of 'XIIC' is incorrect. because you have three lesser values to the left of the greater value. ; only one symbol allowed. The 'C' is in the wrong place. Try CXII = 100 + 10 + 1 + 1 = 112. It is NOT read as (10 + 1 + 1 -(100) = 12 - 100 = 88. '88' in Roman numerals is LXXXVIII. Hope that helps!!!!
What does XIIC in roman numerals?
If it were valid, XIIC would be 88 because: X=10, I=1, C=100 and any smaller number written before a larger one should be deducted from the larger number - so, 10+1+1=12 and 100-12=88. However, 88 would actually be written LXXXVIII (where L=50 and V=5) which is 50+10+10+10+5+1+1+1 as it was the custom to have only one instance of a smaller number before a larger one. For example, 90 is XC (100-10) but 80 is LXXX (50+10+10+10) and 99 is IX (100-1) but 98 is LXLVIII (50+(50-10)+5+1+1+1). However, they did sometimes break the rules - IIC is much easier to write for 98!
