Area = (1/2) x base x height , so solve this for height; height = 2 x Area / base height = (2)(81)/(9) = 18
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
1620 81 times 20 = 1620
(81/4)*(sqrt(3))The area of a triangle is expressed by 1/2 bh, where b is the base length of the triangle, and h is the vertical height. In this instance, the base is equal to 9. The height of an equilateral triangle can be found using the Pythagorean theory with a being half the length of one side of the equilateral triangle, h being the height, and c (the hypotenuse) being the length of one side of the equilateral triangle.Thus,a2+h2=c2(9/2)2+h2=(9)2h2=81-(81/4)h=9(sqrt(3))/2So, A=1/2 bh=1/2 (9)(9(sqrt(3))/2)=(81/4)*(sqrt(3))Area = 1/2 * length * heightheight is square root 2(9)2 = square root 2(81)=square root 192 = 13.85640646...1/2 * 13.85640646 * 9 = 62.3538290 est. to 62.3 square inch
7821 squared 61168041
To calculate the surface area of a regular pyramid, we need the area of the base and the area of the triangular faces. Assuming the base is a square with a side length of 9, the area of the base is (9^2 = 81). The slant height can be calculated using the height of 9 and half the base length (4.5) using the Pythagorean theorem. Finally, the total surface area is the base area plus the area of the four triangular faces.
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
Oh, dude, so you got this triangle with a base of 9 meters and an area of 81 square meters, right? Well, the height of that bad boy is technically 18 meters. Yeah, it's like basic math or whatever. So, there you go, the height is 18 meters, like, no big deal.
242
To find the area of a triangle, you can use the formula A = 1/2 * base * height. In this case, the base is 18 cm and the height is 9 cm. Plugging these values into the formula, we get A = 1/2 * 18 cm * 9 cm = 81 square cm. Therefore, the area of the triangle is 81 square cm.
Do you mean a base of 9 meters? If so then the answer is 18 meters.
9 cm x 9 cm x 12 cm is an isosceles triangle with base 12 and height = sqrt(81-36) cm = sqrt(45) cm So area = 1/2 * base * height = 1/2 * 12 * sqrt(45) = 40.25 cm2
1620 81 times 20 = 1620
Area = 1/2 * 81/16 * 31/7 = 1/2 * 129/16 * 22/7 = 1419/112 = 1275/112
(81/4)*(sqrt(3))The area of a triangle is expressed by 1/2 bh, where b is the base length of the triangle, and h is the vertical height. In this instance, the base is equal to 9. The height of an equilateral triangle can be found using the Pythagorean theory with a being half the length of one side of the equilateral triangle, h being the height, and c (the hypotenuse) being the length of one side of the equilateral triangle.Thus,a2+h2=c2(9/2)2+h2=(9)2h2=81-(81/4)h=9(sqrt(3))/2So, A=1/2 bh=1/2 (9)(9(sqrt(3))/2)=(81/4)*(sqrt(3))Area = 1/2 * length * heightheight is square root 2(9)2 = square root 2(81)=square root 192 = 13.85640646...1/2 * 13.85640646 * 9 = 62.3538290 est. to 62.3 square inch
7821 squared 61168041
Perimeter = 81+81+29 = 191 units of measurement
To calculate the surface area of a regular pyramid, we need the area of the base and the area of the triangular faces. Assuming the base is a square with a side length of 9, the area of the base is (9^2 = 81). The slant height can be calculated using the height of 9 and half the base length (4.5) using the Pythagorean theorem. Finally, the total surface area is the base area plus the area of the four triangular faces.