273K = -0.15ºCUse this equation to convert Kelvin to degrees Celsius/Centigrade: [°C] = [K] - 273.15
If its temperature is 273K - it's Celsius equivalent is 0oC
273
Remember 0 oC = 273K and 100 oC = 373K So subtract 273 from 100,000K = 99727oC
No. If 273K represents 0 degrees Celsius, then 293K will be 20 degrees Celsius, which is lower than 100 degrees Celcius.
-273k
273K = -0.15ºCUse this equation to convert Kelvin to degrees Celsius/Centigrade: [°C] = [K] - 273.15
273K = 0oC Hence 98K = 273K - XoC XoC = 98K - 273K = -175oC
-273k
The freezing point of water is 0°C or 273K in correct SI units.
Freezes.
The lowest possible temperature is -273.15 C which equated to '0'K. Therefore, temperature -273K cannot exist. No -ve K temperatures exist.
273K
B. 273K. 5 degrees Celsius is equal to 278K in the Kelvin scale, but the closest value among the given options is 273K.
At 273K and 1 ATM, most gases typically exist in the gaseous state. However, the specific gas present will depend on the composition of the system.
1C= 273k
No. There are no negative kelvin temperatures.