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Solve u plus v times u-v when you equals 5i plus j and when v equals i-6j?
-1
Simplify 4 square root of 6 divided by square root of 30 reduce first?
4 x V¯6 ---------- V¯30 Simplify V¯6 to V¯3 and V¯2; Simplify V¯30 to V¯10 and V¯3 4 x V¯3 x V¯2 ------------------- V¯10 x V¯3 Simplify V¯10 to V¯5 and V¯2 4 x V¯3 x V¯2 ---------------------- V¯5 x V¯2x V¯3 Cross out V¯3 and V¯2 from both sides. 4 ------- V¯5 Multiply the numerator and denominator by V¯5 (You cannot have a radical in the denominator). 4 x V¯5 --------- <---- Final Answer 5
How do you factor v3 plus 8?
(v + 2)(v^2 - 2v + 4)
How can you use a discriminant to write an equation that has two solutions?
If the discriminant is greater than zero (b^2 - 4ac) > 0, then the equation have two roots that are real and unequal. Further, the roots are rational if and only if (b^2 - 4ac) is a perfect square, otherwise the roots are irrational.Example:Find the equation whose roots are x = u/v and x = v/uSolution:x = u/vx - u/v = 0x = v/ux - v/u = 0Therefore:(x - u/v)(x - v/u) = (0)(0) or(x - u/v)(x - v/u) = 0Let c = u/v and d = v/u. We can write this equation in equation in the form of:(x - c)(x - d) = 0x^2 - cx - dx + CD = 0 orx^2 - (c +d)x + CD = 0The sum of the roots is:c + d = u/v + v/u = (u)(u)/(v)(u) + (v)(v)/(u)(v) = u^2/uv + v^2/uv = (u^2 + v^2)/uvThe product of the roots is:(c)(d) = (u/v)(v/u) = uv/vu = uv/uv = 1Substitute the sum and the product of the roots into the formula, and we'll have:x^2 - (c +d)x + CD = 0x^2 - [(u^2 + v^2)/uv]x + 1 = 0 Multiply both sides of the equation by uv(uv)[x^2 - ((u^2 + v^2)/uv))x + 1] = (uv)(0)(uv)x^2 - (u^2 + v^2)x + uv = 0 which is the equatiopn whose roots are u/v, v/u
How do you solve the following using quadratic formula v2 plus 2v-8 equals 0?
v2+2v-8=0v=[-2±√(2^2+4(1)(8))]/2(1) v=[-2±√(4+32)]/2 v=(-2±6)/2 v=-1±3 v=2 or -4
Solve u plus v times u-v when you equals 5i plus j and when v equals i-6j?
-1
How do you factor v to the power of 6 minus 64?
v^6 -64 = (v - 2)(v + 2)(v^2 - 2v + 4)(v^2 + 2v + 4)
How to factor u to the power of 2 plus uv plus v Please show steps?
u^2 + uv + v has no simple factorisation. As a quadratic in u, it can be "factorised" by using the quadratic formula to find the root values (r1 and r2) for u, and then the factorisation would be (u - r1)(u - r2); however the values of the roots are: r1 = (-v + √(v^2 - 4v))/2 r2 = (-v - √(v^2 - 4v))/2 which leads to the complicated "factorisation": u^2 + uv + v = (u + (v + √(v^2 - 4v))/2)(u + (v - √(v^2 - 4v))/2)
When is Season 2 of V on?
When is season 2 of V be show in the UK
What is the answer Solve the inequality for v 7v and gt 63 Simplify your answer as much as possible?
v * 7v > 637*v^2 > 63 v^2 > 9 v < -3 or v > 3.
What is the answer for S equals 4v2 for v?
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
Simplify 4 square root of 6 divided by square root of 30 reduce first?
4 x V¯6 ---------- V¯30 Simplify V¯6 to V¯3 and V¯2; Simplify V¯30 to V¯10 and V¯3 4 x V¯3 x V¯2 ------------------- V¯10 x V¯3 Simplify V¯10 to V¯5 and V¯2 4 x V¯3 x V¯2 ---------------------- V¯5 x V¯2x V¯3 Cross out V¯3 and V¯2 from both sides. 4 ------- V¯5 Multiply the numerator and denominator by V¯5 (You cannot have a radical in the denominator). 4 x V¯5 --------- <---- Final Answer 5
How fast are you falling if you fall 2 meters?
(u) initial velocity = 0 (a) acceleration due to earths gravity = 9.8 ((m/s)/s) (s) distance = 2m (v) final velocity = ? since v^2 = u^2+(2*a*s) then v^2 = 0 +(2*9.8*2) then v^2 = 39.2 then v = sq root (39.2) v = 6.26 m/s (14 mph)
What is the answer to v-27?
i meant |v-2|=7
How do you factor v3 plus 8?
(v + 2)(v^2 - 2v + 4)
The rate of the velocity of an object?
To calculate the velocity of an object you can use the formula v=d/t. v=velocity, d=distance, and t=time. You can also calculate velocity using a=change in v/change in t, v(final)=v(initial)+at, v(average)=v(final)+v(initial)/2, or v(final)^2=v(initial)^2+2ad, or p=mv.
How can you use a discriminant to write an equation that has two solutions?
If the discriminant is greater than zero (b^2 - 4ac) > 0, then the equation have two roots that are real and unequal. Further, the roots are rational if and only if (b^2 - 4ac) is a perfect square, otherwise the roots are irrational.Example:Find the equation whose roots are x = u/v and x = v/uSolution:x = u/vx - u/v = 0x = v/ux - v/u = 0Therefore:(x - u/v)(x - v/u) = (0)(0) or(x - u/v)(x - v/u) = 0Let c = u/v and d = v/u. We can write this equation in equation in the form of:(x - c)(x - d) = 0x^2 - cx - dx + CD = 0 orx^2 - (c +d)x + CD = 0The sum of the roots is:c + d = u/v + v/u = (u)(u)/(v)(u) + (v)(v)/(u)(v) = u^2/uv + v^2/uv = (u^2 + v^2)/uvThe product of the roots is:(c)(d) = (u/v)(v/u) = uv/vu = uv/uv = 1Substitute the sum and the product of the roots into the formula, and we'll have:x^2 - (c +d)x + CD = 0x^2 - [(u^2 + v^2)/uv]x + 1 = 0 Multiply both sides of the equation by uv(uv)[x^2 - ((u^2 + v^2)/uv))x + 1] = (uv)(0)(uv)x^2 - (u^2 + v^2)x + uv = 0 which is the equatiopn whose roots are u/v, v/u
