The Roman numerals for 49 are XXXXVIIII or IL and notXLIX. In fact the Latin word for IL is undequinquagintawhich quite literally means one from fifty. So your question is: What is IL squared? IL squared = -I(-I+L)+L(-I+L) Multiplying out the brackets = +I-L-L+MMD (+1-50-50+2500) When simplified = CMMDI (2501-100) Therefore 49 squared in Roman numerals = CMMDI (2401) Note that in maths a minus number multiplied by a minus number changes to a plus number. Hence -I times -I is +I. David Gambell, Merseyside, England. Conventionally accept wisdom tells us that XLIX (40 +9) and XLVIIII (40 + 5 + 4) are both mean acceptable methods of writing 49, although the former is more popular as it is shorter. XXXXVIIII is numerically correct but clumsy and unweildy, so it is rarely if ever used. The alternative mentioned above, IL is incorrect on two counts. According to the website Algebra.com Roman numerals read from left to right and always start with the highest value numeral, as I (1) is patently less than L (50) IL is clearly wrong. Also while I may preceed V or X it should not be placed in front of any higher value numerals, such as L. It should also be noted that the answer of 2401 should not be written as CMMDI because it flouts the aforementioned rules in placing CM (900) before M (1000). The accepted correct method of writing 2401 is MMCDI(2000 + 400 + 1).
Roman numerals:IX*IX = LXXXILXXXI/III = XXVIIXXVII+LXXIII = LXXXXVIIIII => CArabic numerals:9*9 = 8181/3 = 2727+73 = 100
Roman numerals were inspired by Etruscan numerals of which Roman numerals originated from.
Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.
Pythagoras' Theorem states that for any right angle triangle the height squared plus the base squared is equal to the square of the hypotenuse. In other words, after finding the square of the hypotenuse, square root your answer to find its length. Hence: (8*8)+(6*6)=64+36=100. The square root of 100=10. Therefore the length of the hypotenuse is 10 inches. In Roman numerals: (VIII*VIII)+(VI*VI)=LXIIII+XXXVI=C. The square root of C=X. Therefore the length of the hypotenuse is X inches. David Gambell, Merseyside, England.
113 = CXIII in Roman numerals
L (50) squared in Roman numerals is MMD (1000+1000+500=2500)
In Roman numerals it is: MMMDC = 3600
The Roman numerals for 11 are XI. To find XI cubed first calculate XI squared snd then multiply this by XI which in effect is XI cubed. XI squared = X(XI)+I(XI) Multlplying out the brackets = CX+XI (110+11) When simplified = CXXI (121) XI times CXXI = X(CXXI)+I(CXXI) Multiplying out the brackets = MCCX+CXXI (1210+121) When simplified = MCCCXXXI (1331) Therefore 11 cubed in Roman numerals = MCCCXXXI (1331) David Gambell, Merseyside, England.
Roman numerals:IX*IX = LXXXILXXXI/III = XXVIIXXVII+LXXIII = LXXXXVIIIII => CArabic numerals:9*9 = 8181/3 = 2727+73 = 100
1000*1002 = 10,000,000. Ten-million.
Roman numerals were inspired by Etruscan numerals of which Roman numerals originated from.
Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.
Pythagoras' Theorem states that for any right angle triangle the height squared plus the base squared is equal to the square of the hypotenuse. In other words, after finding the square of the hypotenuse, square root your answer to find its length. Hence: (8*8)+(6*6)=64+36=100. The square root of 100=10. Therefore the length of the hypotenuse is 10 inches. In Roman numerals: (VIII*VIII)+(VI*VI)=LXIIII+XXXVI=C. The square root of C=X. Therefore the length of the hypotenuse is X inches. David Gambell, Merseyside, England.
In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.
113 = CXIII in Roman numerals
It is: 1830 = MDCCCXXX in Roman numerals
1697 in roman numerals is: MDXCVII.