If you mean: ax2+bx+c = 0 then this is the formula for a quadratic equation whereas a is greater than zero
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
y= ax2+bx+c
Change all the signs. Suppose you have the quadratic equation: y = ax2 + bx + c Its additive inverse is -ax2 - bx - c.
ax2 + bx + c = y
ax2 + bx + c
ax^2+bx+c=0 is the standard form of a quadratic function.
If you mean: ax2+bx+c = 0 then it's the general form of a quadratic equation
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
y= ax2+bx+c
Change all the signs. Suppose you have the quadratic equation: y = ax2 + bx + c Its additive inverse is -ax2 - bx - c.
You complete the squares. y = ax2 + bx + c = (ax2 + b/2a)2 + c - b2/(4a2)
ax2 + bx + c = y
ax2 + bx + c
x = [−b ± √(b2 − 4ac)]/2aA, B, and C can all correspond to the original quadratic equation as follows: ax2 + bx + c = 0The quadratic formula can only be used if the quadratic equation is equal to zero.If [ Ax2 + Bx + C = 0 ], thenx = [ -B +/- sqrt( B2 - 4AC ) ]/ 2A
The standard form of a quadratic equation is ( ax^2 + bx + c = 0 ), where (a), (b), and (c) are constants and (a \neq 0).
ax2 +bx + c = 0
ax2 + bx + c = 0