674
1111 1111 1111 1111 = 2^16 = 65536
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
In FoxPro, you can convert a decimal number to a binary number using the DECIMAL() and STR() functions. First, use DECIMAL() to get the binary representation, then format it as a string using STR(). Here's an example: binaryString = STR(DECIMAL(decimalNumber, 2)). This will give you the binary equivalent of the decimal number.
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.
0.0000001
0.9999
65,535
1111 1111 1111 1111 = 2^16 = 65536
An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.
Using the digits 12279, the largest number that can be represented is 97,221.
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
In FoxPro, you can convert a decimal number to a binary number using the DECIMAL() and STR() functions. First, use DECIMAL() to get the binary representation, then format it as a string using STR(). Here's an example: binaryString = STR(DECIMAL(decimalNumber, 2)). This will give you the binary equivalent of the decimal number.
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
only one zero can be added using a decimal
Using a decimal, of course. All you need do is move the decimal point two places to the right.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.