0
What else can I help you with?
What is the length and width of each face of a cube if the area is 150?
5
How do you find the area of each face on a box?
Each face of a box is a rectangle . The area of a rectangle is (its length) times (its width). Measure the length and width of each face, and multiply (length times width). If you think about what you're doing, and plan it carefully, you only have to make three measurements and you'll have the whole box covered ... all six faces.
What is the width of a nickel in cm?
A nickel has a width/diameter of 21.21mm (2.121cm) and a thickness of 1.95mm (0.195cm).
How do you find a length to width ratio of a face?
You measure the length, L, in some units (inches, centimetres, whatever), measure the width, W, in the same units and then calculate L/W.
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
What is the length and width of each face of a cube if the area is 150?
5
How do you find the area of each face on a box?
Each face of a box is a rectangle . The area of a rectangle is (its length) times (its width). Measure the length and width of each face, and multiply (length times width). If you think about what you're doing, and plan it carefully, you only have to make three measurements and you'll have the whole box covered ... all six faces.
What is the width of a nickel in cm?
A nickel has a width/diameter of 21.21mm (2.121cm) and a thickness of 1.95mm (0.195cm).
How do you find a length to width ratio of a face?
You measure the length, L, in some units (inches, centimetres, whatever), measure the width, W, in the same units and then calculate L/W.
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Nickel has an fcc unit cell with an edge length of 350.7pm calculate the radius of a nickel atom?
The face diagonal of an fcc unit cell can be calculated using the relationship: face diagonal = √2 * edge length. Given the edge length of 350.7 pm, the face diagonal would be 495.2 pm. Since the atom sits on the body diagonal, the radius of a nickel atom can be calculated as half the body diagonal, which is (1/√3) * face diagonal. Calculating this gives a radius of approximately 202.1 pm.
How do you you get the length if you have the area and the width?
Area = length x width Length = area/width
Does a point have length and width but no height?
No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.
How do you find the length if the width and area is given?
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
How do you find the length if you already have the width and the area?
If Length * Width = Area, then Area ÷ width = Length
Where is the length and width location?
Length and width
How many width are in a length?
Length / Width
