The diameter is 21.2 mm, so the radius would be 10.6.
US coins are normally measured in metric units. A nickel is 21.21 mm in diameter. The radius is half the diameter, and there are 25.4 mm in an inch to the radius in inches would be 0.5 x 21.21 / 25.4 = 0.417 inches
The diameter of a nickel is 2.121 cm.To find the perimeter of the nickel, we will use the equation 2(Pi)rTo find the radius, r, divide the diameter by 2.2.121/2=1.0605P = 2(3.14159)(1.0605)= 6.6633 cmTherefore, the perimeter of a nickel is approximately 6.66 cm.
First off, area is in square cm while distance is in cm. The radius of a nickel is 1.0605 cm, so using the famous formula pi x r2 for the area gives: 3.141593 x 1.06052 = 3.5332 cm2
No. Radius is half of the diameter.
(radius+radius) times pi
The element nickel (Ni) has an atomic radius of 124 picometers.
The standard diameter of a US nickel is 21.2 mm so its radius is half that, or 10.6 mm
Platinum; it has two more electron shells than nickel.
The atomic radius of nickel is not directly calculated but is typically determined experimentally using X-ray crystallography or other techniques. The atomic radius is defined as half the distance between the nuclei of two adjacent atoms in a crystal lattice. For nickel, the atomic radius is approximately 0.124 nm.
US coins are normally measured in metric units. A nickel is 21.21 mm in diameter. The radius is half the diameter, and there are 25.4 mm in an inch to the radius in inches would be 0.5 x 21.21 / 25.4 = 0.417 inches
This may vary by your 'definition' of 'bigger'Atom radius Cu: 128 pM, Ni: 124 pM orVanderWaals radius Cu: 140 pM, Ni: 163 pM
The dime has the smallest diameter among the listed coins, making it the coin with the smallest radius.
The inner core is approximately 1271 kilometers in radius and is composed of iron and nickel, the liquid outer core is 2270 kilometers radius, and the radius of the mantle, the thickest solid layer, is 2885 kilometers.
The diameter of a nickel is 2.121 cm.To find the perimeter of the nickel, we will use the equation 2(Pi)rTo find the radius, r, divide the diameter by 2.2.121/2=1.0605P = 2(3.14159)(1.0605)= 6.6633 cmTherefore, the perimeter of a nickel is approximately 6.66 cm.
The face diagonal of an fcc unit cell can be calculated using the relationship: face diagonal = √2 * edge length. Given the edge length of 350.7 pm, the face diagonal would be 495.2 pm. Since the atom sits on the body diagonal, the radius of a nickel atom can be calculated as half the body diagonal, which is (1/√3) * face diagonal. Calculating this gives a radius of approximately 202.1 pm.
The planet with a core of nickel and iron and a crust 600 km thick is Mercury. Mercury's core makes up about 85% of its radius and is composed mainly of iron with some nickel. Its crust is thin compared to its core and mantle.
iron (85 %) with some (4-5%) nickel and the remainder oxygen, silicon, hydrogen and carbon