You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
5s - 3 = 3s - 92s = -6s = -3
3s-4
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
Every 30 numbers you end up in the 10s place when you count by 3s. 30,60,90
You should split in blackjack when you have a pair of 2s, 3s, 6s, 7s, or 9s, according to the chart.
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p
Area rectangle = Area of Square (s - 2) x 3s = s2 3s2 - 6s =s2 2s2 - 6s =0 s2 - 3s =0 s(s-3) =0 S= 0, S= 3
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
Yes, it exists. If you write the orbitals in order of increasing energy, then you get it. The order is:- 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p..................... Here, you get the 3s orbital at the 4th place.
36 playing cards in a Russian deck. Russian deck starts with 6s. There are same four suits as American deck but 2s, 3s, 4s and 5s are missing.
-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s
The order of electron orbitals following the Aufbau principle is: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p. Electrons fill the orbitals in increasing energy levels.