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A force of 1000n is exerted on piston 1 what will be exerted on piston 2?
Wiki User
∙ 13y ago
If this is about a hydraulic system, same pressure acts through out the fluid.
Take,
A = cross sectional area (area normal to force) of piston 1
B = "" "" "" of piston 2
F2 = Force on 2nd piston
So, pressure = 1000/A = F/B
Therefore, F = (1000 X B/A ) N
(The force depends on the area ratio)
Wiki User
∙ 13y ago
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