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If this is about a hydraulic system, same pressure acts through out the fluid.

Take,

A = cross sectional area (area normal to force) of piston 1

B = "" "" "" of piston 2

F2 = Force on 2nd piston

So, pressure = 1000/A = F/B

Therefore, F = (1000 X B/A ) N

(The force depends on the area ratio)

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