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They height y of the projectile is given by the function y = vosin(0)t + 1/2gt2, where vo is the initial velocity of the projectile, 0 is the firing angle, t is the time, and g is the acceleration of gravity (-9.81m/s2). The range x of the projectile is given by the function x = vocos(0)t. Rearranging this last equation for time yeilds t = x/(vocos(0)); this will give us the length of time the projectile takes to reach the target. Substituting this into the first equation yeilds:

y = vosin(0)[x/(vocos(0))] + 1/2g[x/(vocos(0))]2

this can be simplified further but it is not necessary to do so; plugging it the x and y coordinates, the initial velocity, and the acceleration of gravity, you should be able to solve for 0, which is now the only unknown.

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Q: How do you find the firing angle for a projectile given the targets x and y coordinates and initial velocity I would like to do it without calculus if possible.?
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