for M6 is 1N.m and for M8 is 2.2N.m
You you you
it means BROTHER
That depends on the context. For instance, when using a number in certain programming languages (such as Java, or Python 2.x), it may mean that the number should be treated as a "long".
carnot cycle?
Date stamp of 1890
Suppose that you have simple two variable model: Y=b0+b1X1+e The least squares estimator for the slope coefficient, b1 can be obtained with b1=cov(X1,Y)/var(X1) the intercept term can be calculated from the means of X1 and Y b0=mean(Y)-b1*mean(X1) In a larger model, Y=b0+b1X1+b2X2+e the estimator for b1 can be found with b1=(cov(X1,Y)var(X2)-cov(X2,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) to find b2, simply swap the X1 and X2 terms in the above to get b2=(cov(X2,Y)var(X1)-cov(X1,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) Find the intercept with b0=mean(Y)-b1*mean(X1)-b2*mean(X2) Beyond two regressors, it just gets ugly.
the m means motorsport
Each element is the mean of the corresponding elements. Thus, the mean of (x1, y1) and ( x2, y2) is [( x1 + x2)/2, (y1 + y2)/2]
If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.
The answer depends on absolute deviation from what: the mean, median or some other measure. Suppose you have n observations, x1, x2, ... xn and you wish to calculate the sum of the absolute deviation of these observations from some fixed number c. The deviation of x1 from c is (x1 - c). The absolute deviation of x1 from c is |x1 - c|. This is the non-negative value of (x1 - c). That is, if (x1 - c) ≤ 0 then |x1 - c| = (x1 - c) while if (x1 - c) < 0 then |(x1 - c)| = - (x1 - c). Then the sum of absolute deviations is the above values, summed over x1, x2, ... xn.
m6 is bigger
A set of numbers will have a mean, which is defined as the sum of all the values divided by the number of values. Suppose this mean is m. For each of the values, the squared deviation is the square of the difference between that value and m. Algebraicly, if you have a set {x1, x2, x3, ... , xn}, whose mean is m, then the squared deviation from the mean for x1 is (x1 - m)2.
The geometric mean of 'A' and 'B' is the square root of ( A x B ). Edit: The geometric mean of n positive numbers, x1, x2, ... , xn is the nth root of x1*x2* ... *xn.
Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.Nothing. There is no such Roman numeral as X1. If you mean XI, then the numeral is eleven. XI would be the year 11 either BC or AD.
Aaron Poison/Bug x1 Bug/Fighting x1 Bug/Flying x2 Poison/Dark x1 Bertha Water/Ground x2 Ground x1 Rock x1 Rock/Ground x1 Flint Fire x1 Fire/Fighting x1 Steel/Ground x1 Normal x1 Ghost/Flying x1 Lucian Psychic x2 Normal/Psychic x1 Fight/Psychic x1 Steel/Psychic x1 Cynthia Ghost/Dark x1 Dragon/Ground x1 Water/Ground x1 Water x1 Grass/Poison x1 Steel/Fighting x1
M6 - 81 = M6 - 92 = (M3 - 9)(M3 + 9) [difference of two squares]