depends... were they homozygous or heterozygous?
The mother will produce two types of gametes: IA and IO (mother is A) The father is AB his genotype is IAIB, thus he will produce these kind of gametes: IA and IB Four combinations are possible IA from Mother and IA from Father: The child has genotype IAIA and he has blood group A IO from Mother and IA from Father: The child has genotype IAIO and he has blood group A IA from Mother and IB from Father: The child has genotype IAIB and he has blood group AB IO from Mother and IB from Father: The child has genotype IBIO and he has blood group B Thus the phnotypic ratio is blood group A:B:AB = 2:1:1
Assuming baldness is a trait determined by a dominant allele (B for bald, b for not bald), if the mother is bald (genotype BB or Bb) and the father is not bald (genotype bb), the offspring's genotypic ratio will depend on the mother's genotype. If the mother is BB, all offspring will be Bb (bald), resulting in a phenotypic ratio of 100% bald. If the mother is Bb, the genotypic ratio will be 1 Bb : 1 bb, leading to a phenotypic ratio of 50% bald and 50% not bald.
Because the actuality of IAIA is actually A then the father would be type A and the mother being type O they would produce children of Type A blood type. For the answer I chose A) A... I just had this on my Bio exam.
When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.
To predict the genotypic and phenotypic ratios, we first need to establish the alleles for boldness. Let's assume boldness (B) is dominant and non-boldness (b) is recessive. If the mother is bold, she could be either homozygous (BB) or heterozygous (Bb). If the father is not bold, he is homozygous recessive (bb). If the mother is BB, all offspring will be bold (100% phenotypically bold, BB genotype). If the mother is Bb, the offspring will have a genotypic ratio of 1 BB: 1 Bb (100% bold), resulting in a phenotypic ratio of 100% bold. In summary, regardless of the mother's genotype, all offspring will exhibit the bold phenotype.
To determine the genotype ratio from the given genotypes (fF, fF, ff, ff), we first count each genotype. There are 2 fF and 2 ff. The genotype ratio can be expressed as 2 fF : 2 ff, which simplifies to 1 fF : 1 ff. Thus, the genotype ratio is 1:1.
For monohybrid cross the genotype ratio in f2 generation would be 1:2:1 and phenotype ratio would be 3: 1
The resulting generation will have a 1:1 ratio of RR to rr genotypes when crossing an Rr genotype with a rr genotype, as each parent will contribute one allele to the offspring.
The predicted ratio of offspring in a mating of AAA and AAA would be 100% AAA. Since both parents have the same genotype, all of their offspring will inherit the same genotype.
The genotype is the actual code for a trait. Hidden on the chromosome we can never actually see the alleles controlling the trait unless we sequence the DNA. The phenotype is the result of at least two alleles expressing a visible or measurable trait in an individual. A genotype to phenotype ratio is the correspondence between the unseen code of the individual's alleles and the detectable quality of the individual's trait. This ratio relates the proportional quantities of unseen and seen, a comparison between the encoded trait and the expressed result of the code.
When crossing an Aa individual (heterozygous) with an An individual (where 'n' represents a different allele, such as 'aa'), the possible genotypes in the offspring would be Aa, Aa, An, and An. This results in a genotype ratio of 2 Aa: 2 An, or simplified, 1 Aa: 1 An. Therefore, the expected genotype ratio in the next generation would be 1 Aa: 1 An.
In mice the YY genotype is lethal during embryonic development. This means that the mating of heterozygous individuals will produce a ratio of 2:1 Yy to yy offspring.A 'YY' genotype is homozygous dominant for that particular trait. If it is Yy, it will be heterozygous.