B r t in text abbreviation means be right there
B r t in text abbreviation means be right there
b***h running after tony
B T R stands for the band formaly known as big time rush
b a r t e r (:
R/T refers to Road and Track
3 blind mice see how they run.
3 blind mice, see how they run
b a r t e r (:
r-a-b-b-i-t
what mean of this question mail me my email address M I S I S U O Y B H T A E R Y email address is afteryoume@yahoo.com
Linear algebra deals with mathematical transformations that are linear. By definition they must preserve scalar multiplication and additivity. T(u+v)= T(u) + T(v) T(R*u)=r*T(u) Where "r" is a scalar For example. T(x)=m*x where m is a scalar is a linear transform. Because T(u+v)=m(u+v) = mu + mv = T(u) + T(v) T(r*u)=m(r*u)=r*mu=r*T(u) A consequence of this is that the transformation must pass through the origin. T(x)=mx+b is not linear because it doesn't pass through the origin. Notice at x=0, the transformation is equal to "b", when it should be 0 in order to pass through the origin. This can also be seen by studying the additivity of the transformation. T(u+v)=m(u+v)+b = mu + mv +b which cannot be rearranged as T(u) + T(v) since we are missing a "b". If it was mu + mv + b + b it would work because it could be written as (mu+b) + (mv+b) which is T(u)+T(v). But it's not, so we are out of luck.
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)