If your peice of concrete does not have beams I consider that flatwork. So in flatwork with 3/8 rebar (#3) on 16" centers, for the 15 foot side you will have 8 pieces x 15' long. On the 10' side you will need 12 pieces x 10'. (6 bars cut in half) In all you will need 14 #3 x 20'
A minimum of 1.3 cubic yards.
To determine how many bags of concrete you need for a 10 x 10 slab, first calculate the volume: a 4-inch thick slab is 10 x 10 x (4/12) = 33.3 cubic feet. A typical 80-pound bag of concrete covers about 0.6 cubic feet. Dividing 33.3 by 0.6 means you would need approximately 56 bags of concrete for that size slab.
A 10-foot round slab at 4 inches requires 1 cubic yard.
I think you mean "How much area will 4 yards of concrete cover?". It depends on the slab thickness and whether or not anything significant is embedded (a lot of rebar, conduit, etc.). If working in feet, measure the width length and depth, multiply these numbers then divide the result by 27 to calculate the volume in cubic yards. A slab 9' 6" by 10' 4" by 6" thick translates to 9.5x10.3x.5 (48.93) /27 = 1.8 yards. Since you already have the volume, you will need to play with some of the dimensions to find something that works.
one yard of cement will make a 8 x 10 square foot slab at 4 inches thick, that's 80 sq. feet per yard of cement at 4 inches thick.
15mm;density is 7851 kg/m3 unit wt = pi x (radius2) x 7851 kg/m3 = 1.387 kg/m
To determine how many slabs of size 450 mm x 450 mm are needed for an area of 10 m², first convert the slab dimensions to square meters. Each slab is 0.45 m x 0.45 m, which equals 0.2025 m² per slab. Therefore, to cover 10 m², you would need 10 m² ÷ 0.2025 m²/slab ≈ 49.38 slabs. Since you can't have a fraction of a slab, you would need 50 slabs.
You'll need 1.23 Cubic Yards.
10-ft x 30-ft x 4-in = 100 cubic ft.That slab weighs 3.7 times as much as 1 "yard" of concrete. (rounded)
1.85 cubic yards.
10 cm = 0.1 meterThe volume of the slab is (6 x 8 x 0.1) = 4.8 cubic meters
A minimum of 1.23 cubic yards at 4" thick.