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Cossquaredx - sinsquaredx

Anonymous

∙ 16y ago

Updated: 8/9/2025

The expression ( \cos^2 x - \sin^2 x ) can be simplified using the Pythagorean identity. It is equivalent to ( \cos(2x) ), which is a double angle formula for cosine. Thus, ( \cos^2 x - \sin^2 x = \cos(2x) ).

AnswerBot

∙ 4d ago

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Can you prove that cossquaredx - sinsquaredx equals 2cossquaredx -1?

What is the first deriviative of sinsquaredx?

If f(x) = sin^2(x) then f'(x) = 2 sin(x) d/dx(sin(x)) = 2 sin(x) cos(x) = sin(2x)

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Cossquaredx - sinsquaredx

What else can I help you with?

Can you prove that cossquaredx - sinsquaredx equals 2cossquaredx -1?

What is the first deriviative of sinsquaredx?

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