This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.
However, if the diagonals are perpendicular bisectors, then we have a rhombus.
Consider quadrilateral ABCD, with diagonals intersecting at X, where
AC and BD are perpendicular;
AX=XC;
BX=XD.
Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.
By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.
This means that AB=BC=CD=DA.
Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
ABCD is a parallelogram => AB is congruent to DC and AD is congruent to BC.
Then, AD is congruent to AB => all four sides are congruent.
Thus ABCD is a parallelogram with four congruent sides. Therefore, by definition it is a rhombus.
It is not possible to prove it because it is not true!
Not in general. The diagonals of a rectangle are equal length. A rhombus that is also a rectangle would be a square.
The diagonals of any rhombus bisect each other. A square is a special kind of a rhombus.
They bisect each other at an angle of 90 degrees
Yes. The diagonals of any parallelogram bisect each other. A rectangle is a special case of a parallelogram.
Yes the diagonals of a parallelogram have the same midpoint since they bisect each other.
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Not necessarily.
Yes and the diagonals are not equal in length
Square, Rhombus
Not a quadrilateral. But "Yes" to a rhombus and a rectangle. And, since a square is a rectangle as well as a rhombus, a square as well.
Parallelogram and rhombus.
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
A square, a rhombus and a kite have diagonals that intersect each other at right angles.
It is a rhombus or a kite
It makes sense because it is true. There are other quadrilaterals whose diagonals are perpendicular.
The diagonals of any parallelogram (square, rhombus, rectangle, rhomboid) bisect each other. The difference is the the diagonals are equal in length for a square and rectangle, and not equal for a rhombus or rhomboid (oblique diamond).
A quadrilateral is a type of polygon that has four corners and sides. It is called a parallelogram (rectangle, square, or rhombus) when its diagonals bisect to each other.