This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.
However, if the diagonals are perpendicular bisectors, then we have a rhombus.
Consider quadrilateral ABCD, with diagonals intersecting at X, where
AC and BD are perpendicular;
AX=XC;
BX=XD.
Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.
By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.
This means that AB=BC=CD=DA.
Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
In mathematical terms, a diamond shape is often referred to as a "rhombus." A rhombus is a type of quadrilateral where all four sides are of equal length, and opposite angles are equal. Additionally, the diagonals of a rhombus bisect each other at right angles.
Not in general. The diagonals of a rectangle are equal length. A rhombus that is also a rectangle would be a square.
The diagonals of any rhombus bisect each other. A square is a special kind of a rhombus.
They bisect each other at an angle of 90 degrees
Yes. The diagonals of any parallelogram bisect each other. A rectangle is a special case of a parallelogram.
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Not necessarily.
Yes and the diagonals are not equal in length
Square, Rhombus
While it is true that if a quadrilateral has perpendicular diagonals, it can indicate that the shape is a rhombus, this condition alone is not sufficient for classification. Other quadrilaterals, such as kites, can also have perpendicular diagonals. Therefore, while perpendicular diagonals are a characteristic of rhombuses, they do not definitively determine that a quadrilateral is a rhombus without additional properties being met.
Not a quadrilateral. But "Yes" to a rhombus and a rectangle. And, since a square is a rectangle as well as a rhombus, a square as well.
Parallelogram and rhombus.
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
A square, a rhombus and a kite have diagonals that intersect each other at right angles.
It is a rhombus or a kite
It makes sense because it is true. There are other quadrilaterals whose diagonals are perpendicular.
The diagonals of a rhombus are always congruent. A rhombus is a quadrilateral with all sides of equal length. Due to its symmetry, the diagonals of a rhombus bisect each other at right angles, and they are always of the same length. This property distinguishes a rhombus from other quadrilaterals like rectangles or parallelograms.