We know -1=-1, make these two into different but equivalent fractions -1/1=1/-1, take the square root of both sides sqrt(-1/1)=sqrt(1/-1), the rule sqrt(x/y)=sqrt(x)/sqrt(y) is true so we can write... sqrt(-1)/sqrt(1)=sqrt(1)/sqrt(-1), simplify the fractions i/1=1/i, multiply both sides by i -1/1=i/i, i/i=1 and -1/1 is -1 so we can write... -1=1 There's your proof i=sqrt(-1) spoiler:i is imaginary
SAS
Prove it by induction on n, use 0 or 1 as base cases.
If x is a null matrix then Ax = Bx for any matrices A and B including when A not equal to B. So the proposition in the question is false and therefore cannot be proven.
A - B is null.=> there are no elements in A - B.=> there are no elements such that they are in A but not in B.=> any element in A is in B.=> A is a subset of B.
The product of a number and 1 over that number equals one.
You can't it equals 2. You can't it equals 2.
a0=(a-1\a-1)=a\a=1
Using faulty logic.
Using a calculator
No, because technically, it is not true.
It isn't equal, and any proof that they are equal is flawed.
If xyz=1, then it is very likely that x=1, y=1, and z=1. So plug these in. 1=logbase1of1, 1=logbase1of1, 1=logbase1of1. You end up with 1=1, 1=1, and 1=1. That's your proof.
Cannot prove that 2 divided by 10 equals 2 because it is not true.
(a to the power of 1)/(a to the power of 1)=1 So, a to the power of (1-1)=1 Therefore, a to the power of 0=1
sin4x=(4sinxcosx)(1-2sin^2x)
There is no proof. 1 mechanical horse power is simply defined as 745.7 watts. Period.
No you can not prove that 9 +10 = 21.