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The relationship between the percent volume (not reached by the stain) and the surface area-to-volume ratio would be that the bigger the agar cube size (surface area to volume ratio), the bigger the percent volume. This is true because resources need to travel a farther distance through the cell ("cover more ground", so to speak) in order to be evenly distributed through the cell.
Drag. This is the force which acts against a runner and is the resultant force of the runner pushing against the particles in the air. Drag is affected by the mass and surface area of the runner. Friction is another force which can affect running.
Fracturing increases the surface area of a rock exposed to weathering.
the difference between this is that surface area
The shape affects the ratio of surface area to volume. The greater the surface are to volume ratio, the faster the magma will cool.
due to surface area. if you are taller your lungs will have a greater surface area which will raise the volume.
The flatter the cell, the surface-area will increase, however the volume will remain the same
The surface area of mitochondria or chloroplast affect its energy output because larger surfaces-to-volume ratio imply more loss of energy as opposed to smaller surface-to-volume ratios.
To obtain the ratio of surface area to volume, divide the surface area by the volume.
surface area/ volume. wider range of surface area to volume is better for cells.
Larger surface area can be favourable to increased rated of exchange whereas greater cell volume can be unfavourabe. Being a three dimensional structure the rate in which volume grows is higher than the rate of surface area growth.
The surface-area-to-volume ratio may be calculated as follows: -- Find the surface area of the shape. -- Find the volume of the shape. -- Divide the surface area by the volume. The quotient is the surface-area-to-volume ratio.
The rate of combustion directly proportional to the surface area of combining naterials
the cell's ability to feed enough
Volume does not, surface area does.
Volume=area * length of that surface