One of the beauties of an integrated circuit is that you can regard the package as
a 'black box' characterized by its published operating parameters, and you don't
need to analyze the internal circuit.
If you've been assigned to analyze the internal circuit, then you're part of a class
or group of people who have been given the tools necessary to do it. Just go
ahead and dig into the nine transistors there in the LM386. There's a single-stage
differential amplifier with a few feedback components, and there's also what appears
to be a voltage regulator. There's not really that much in there, and you shouldn't be
scared off by the use of PNP and NPN transistors in cascade.
The whole thing is just an academic exercise anyway ... notice that the drawing
in the data sheet is labeled "equivalent schematic", and doesn't really represent
everything that's actually on the chip.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
Please see the Related Link shown below.
The duration of Analyze That is 1.6 hours.
The duration of Analyze This is 1.72 hours.
As it ages, its Kirchhoff virtual 'internal resistance' increases. Pictured this way, the practical effect is that the open-circuit voltage of a failing cell still measures good, but the voltage quickly sags when you try to draw any current from it
the lm386 is used mainly as a audio ampplifier to power small speakers or headphones
LM stands for "Linear Monolithic"
Use a test light to analyze the circuit. Use a test light to analyze the circuit.
basic circuit of electrical protective relay
unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance
Yes it can, if there is an internal short circuit.
In a closed circuit there is a potential drop due to resistance of wires and battery (internal).AnswerWhen the circuit is closed, the resulting current not only flows through the external circuit, but through the source (battery, generator, transformer, etc.) itself. All sources have an internal resistance, which causes an internal voltage drop, slightly reducing the voltage across the terminals. The larger the current, the larger the internal voltage drop, and the lower the terminal voltage.When the circuit is open, no current flows. So there is no internal voltage drop, and the full voltage appears across the source's terminals.The 'open-circuit voltage' is actually the electromotive force provided by the source.
Batteries are rated as ampere/hour any circuit that draws power from it effects it. The lower the internal resistance of the circuit the shorter the useful battery life as discharged.
In circuit equivalence, voltage and current sources are respectively equated to short and open ckt because of the very nature of them. A voltage source has zero internal resistance and current source has infinite internal resistance hence their equivalents:-)
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
internal diagram of ic 7812