The answer you need is found in "Ohms Law." It is expressed like this: Current = watts divided by volts Watts = Volts multiplied by current Volts = Watts divided by current. I recommend you look into the hobby of Amateur Radio and put your knowledge of electronics to a fun use. My wife and I are both 'hams' and love the hobby!
If running at 110V, that is 10Amps. Wattage = Voltage x Current Current = Wattage / Voltage - Neeraj Sharma
A typical multimeter measures voltage and resistance "in parallel" or current in-line with the circuit. It all depends on the model. 'Multi' means many different modes. Some have more than others. Some multimeters can measure current, but require you to alter the lead configuration and plug into different sockets. If you have the meter set for Current measurement and you put it in parallel instead of series, it will cause a dead short and could damage the meter. (They usually have a fuse inside for protection). Knowing any two of the three parameters you can calculate the third by Ohm's Law: Voltage = Current x Resistance. Knowing Current and Voltage you can calculate power as Volts x Amps = Watts for resistance loads.
Take your circuit voltage and the power of the appliances and divide.E is voltage I is amperage and P is power or wattage. P=ExI Example. 3500 watt heater draws ? Amps on 220Volts I=P/E I= 3500w/220v I= 15.9Amps
A "kilo" means 1000. So a kilowatt is a thousand watts. The same applies to voltage. A kilovolt is 1000 volts. Wattage is the measurement of "electrical power". Voltage is the measurement of "electrical potential" See "Ohms Laws" for more explanation of electrical terms.'
Scroll down to related links and look at "Electricity and Electric Charge - Electrical voltage V, amperage I, resistivity R, impedance Z, wattage P".
To calculate wattage, you need to multiply the voltage (V) by the current (I). The formula is: Wattage (W) = Voltage (V) x Current (I). This formula applies to electrical circuits where the voltage is known and the current is flowing.
Current depends on the Wattage and the voltage rating of the device.
Current.
You'd need to know either the resistance or the wattage of the circuit. Ohm's Law: Current = Voltage divided by resistance or Current = Power divided by Voltage
No, the electrical meter reads watts by multiplying the voltage and the amperage used in electrical circuits. Using oversize wire does not govern the amperage flow to the load. The load resistance in the circuit is what governs the amount of current that flows through the wire. This current in the load circuit is multiplied by the voltage applied to the circuit at the electrical meter. The product of this multiplication is wattage, multiplied by the amount of time the load is on, is what the electrical utility bill is based on.
A watt is a measure of electrical power. If you want to know how much current a circuit will draw, and you have wattage ratings of appliances or devices then you can calculate the current. {Power = Voltage × Current}. On a 110 Volt circuit, you can add up the wattages and then divide by 110 volts, to get current in amperes.
It depends by how much it changes. Power (watts) = current (amps) x voltage If the current halves and the voltage doubles, the power won't change. But if the current is cut in half and the voltage only goes up by a little bit the watts will go down. If the current only goes down a little bit but the voltage doubles, then the watts will go up.
To find the actual wattage of an electrical component, you can calculate it by multiplying the voltage across the component by the current flowing through it, using the formula Watts = Volts * Amps. Alternatively, you can refer to the product specifications provided by the manufacturer, which usually list the wattage of the component.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Common sense with electrical systems dictates that current in a circuit be limited to 80% of nameplate (20A). The number of 150W lamps will be limited to 12 in this scenario. This answer can be superseded by local ordinance.