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Q: How do you finish day 2 of classroom 1?
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A does 1/6 of the work in 1 day. B does 1/4 of the work in 1 day. Assuming there is no synergy, A and B, together do 1/6 + 1/4 = 5/12 of the work in 1 day A worked for 2 days so completed 2*(1/6) = 1/3 of the work. So 2/3 of the work remained to be done by A and B together. They would do it in (2/3) / (5/12) = (2/3) * (12/5) =24/15 = 8/5 = 1.6 days. The total time to finish the work is 2 days + 1.6 days = 3.6 days.


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The Number of men required is 160 Explanation: Let no. of men = m1 = 10 Let no. of days required = d1 = 8 Let no. of men required to finish the work in 1/2 days = m2 Let no of days required for m2 men = 1/2 Now we have to find the no. of men required to complete the work in 1/2 day so the calculation will be, m1d1 = m2d2 (10)(8) = m2(1/2) 80 = m2(1/2) [ By taking the dividend 2 left side it will go into multiple ] 80 x 2 = m2 160 = m2 Therefore, Number of men required to finish the work in 1/2 day is **160 men**