When considering standard household electricity, it will likely be a 120V circuit. Ohm's law says current equal voltage divided by resistance (I = V/R). Watts are a unit of power and are I * V.
Assuming a standard lightbulbs of the same general type, higher wattage / hr indicates a greater brightness. With Voltage held constant in this power equation at V=120V, this indicates higher currents will produce a brighter light. Going back to Ohm's law, this is achieved by reducing the resistance.
By definiton, "dark" matter neither emits or absorbs light. Thus, it does not effect the brightness of galaxies.
Rip current affect the shape of theass
The brightness as seen from Earth is called the "apparent magnitude".The real brightness (defined as the apparent brightness, as seen from a standard distance) is called the "absolute magnitude".
Increase or decrease in potential results in the change in direction of the flow of electric current.
Electric current, magnetic field intensity, length of the conductor, angle between the electric current and magnetic field
Adding more wires in parallel will not affect the brightness of the bulb. Each wire creates a separate pathway for current flow, so dividing the current among multiple wires will not change the total amount of current flowing through the bulb and therefore will not impact its brightness.
Added resistance in a circuit will decrease the current flowing through the circuit, resulting in a decrease in the brightness of the bulb. This is because the bulb's brightness is directly proportional to the current passing through it. More resistance means less current, which leads to reduced brightness.
More current = More brightness
Yes, there may be a difference in bulb brightness depending on factors like the voltage applied, resistance in the circuit, and the type of bulb used. These factors can affect the current flowing through the bulb, ultimately impacting its brightness.
It can, but it should not. If it does, then the reed-switch is defective ... its contacts have most likely deteriorated on account of excessive current at some time.
Increasing resistance in a circuit will decrease the current flowing through the bulb, resulting in reduced brightness. This is because the resistance restricts the flow of electrons and diminishes the amount of energy reaching the bulb to produce light.
The brightness of a bulb is directly related to the amount of power it consumes. The higher the wattage of the bulb, the brighter it will be. Additionally, factors like the type of bulb (incandescent, LED, fluorescent) and the age of the bulb can also affect its brightness.
brightness will decrease
yes
The factor that primarily affects the brightness of a bulb is the amount of electrical current flowing through it. The brightness of a bulb is directly proportional to the current passing through it, as described by Ohm's Law (V=IR), where V is voltage, I is current, and R is resistance. Therefore, increasing the current flowing through the bulb will result in a brighter light output.
Two factors that affect a star's apparent brightness are: 1.) The distance between the Earth and the star 2.) The absolute magnitude (the actual brightness) of the star Hope that helps :P
A variable resistor can be connected in series with a light bulb in a circuit. By adjusting the resistance of the variable resistor, the current flowing through the circuit changes, affecting the brightness of the light bulb. Increasing the resistance decreases the current, resulting in lower brightness, while decreasing the resistance increases the current, leading to higher brightness.